WebFactor a^3-b^6. a3 − b6 a 3 - b 6. Rewrite b6 b 6 as (b2)3 ( b 2) 3. a3 − (b2)3 a 3 - ( b 2) 3. Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 … WebOct 12, 2024 · Let us understand the execution line by line. Initial values of a and b are 1. // Since a is 1, the expression --b // is not executed because // of the short-circuit property …
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WebWithout making any assumption, just simple AM ≥ GM a3 + a3 + b3 ≥ 3a2b b3 + b3 + c3 ≥ 3b2c c3 + c3 + a3 ≥ 3c2a a3 + b3 + c3 ≥ a2b + b2c + c2a. Just assume, wlog a ≤ b ≤ c. Then this equation is all you need: a3 + b3 + c3 = a2b + b2c + c2a + (c2 − a2)(b − a) ⏟ ≥ 0 + (c2 − b2)(c − b) ⏟ ≥ 0 ≥ a2b + b2c + c2a. WebJava actually uses Unicode, which includes ASCII and other characters from languages around the world. ASCII Table Dec = Decimal Value Char = Character '5' has the int value 53 if we write '5'-'0' it evaluates to 53-48, or the int … fsis inspector in charge
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WebSep 6, 2024 · The answer is the option (1). Explanation: Here the expression a**b*a + *b uses pointer in C/C++ concept. Here a**b*a + *b means 5* (value of pointer b that is 5)*5 + (value at pointer b which is 5 again). So the result is 130. 2. What will be the output of following program? #include int main () { int i, j = 3; float k = 7; i = k % j; WebJan 31, 2024 · Answer (1 of 6): They should be the same on a modern compiler, but they look different. The first one only initialized two values of the three explicitly; the third … WebChar &# 36 % ... Char &# 37 & ... Char &# 38 ' ... Char &# 39 ( ... Char &# 40 ) ... Char &# 41 * ... Char &# 42 + ... Char &# 43 , ... Char &# 44 gifts for someone who loves the ocean